Implement subscription management and ordering

This commit is contained in:
2022-07-21 13:48:18 +01:00
parent e0390f383c
commit a30e2afdd1
12 changed files with 170 additions and 22 deletions

View File

@@ -1,14 +1,19 @@
import logging
import stripe
from django.contrib.auth.models import AbstractUser
from django.db import models
from core.lib.customers import get_or_create, update_customer_fields
logger = logging.getLogger(__name__)
class Plan(models.Model):
name = models.CharField(max_length=255, unique=True)
description = models.CharField(max_length=1024, null=True, blank=True)
cost = models.IntegerField()
product_id = models.UUIDField(null=True, blank=True)
product_id = models.CharField(max_length=255, unique=True, null=True, blank=True)
image = models.CharField(max_length=1024, null=True, blank=True)
def __str__(self):
@@ -23,11 +28,11 @@ class User(AbstractUser):
last_payment = models.DateTimeField(null=True, blank=True)
paid = models.BooleanField(null=True, blank=True)
plans = models.ManyToManyField(Plan, blank=True)
email = models.EmailField(unique=True)
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
self._original = self
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
self._original = self
def save(self, *args, **kwargs):
"""
@@ -48,8 +53,19 @@ def __init__(self, *args, **kwargs):
super().save(*args, **kwargs)
def delete(self, *args, **kwargs):
if self.stripe_id:
stripe.Customer.delete(self.stripe_id)
logger.info(f"Deleted Stripe customer {self.stripe_id}")
super().delete(*args, **kwargs)
def has_plan(self, plan):
if not self.paid: # We can't have any plans if we haven't paid
return False
plan_list = [plan.name for plan in self.plans.all()]
return plan in plan_list
class Session(models.Model):
email = models.EmailField()
session = models.CharField(max_length=255)